∠a + ∠d = 180° [Linear Pair] ∠2 = ∠3 [Alternate interior angles] (b) p is true and q is false No, two acute angles cannot form a pair of supplementary angles. If the sum of measures of two angles is 180° then they are _________ The difference of two complementary angles is 30°. Solution : Question 110: We have, Maths Lines and Angles part 1 (Basics of Geometry) NCERT Exemplar Class 7 Maths is very important resource for students preparing for VII Board Examination. z + y = 180° [Linear pair] Also, ∠EFG = ∠1 + ∠2 – 34° +45° = 79° Solution: With this article, you will get solutions to all the questions of CBSE Class 7 Maths, Chapter 5 – Lines and Angles. Solution : Write all the pairs of adjacent angles by taking angles 1, 2, 3 and 4 only. The angle The angles x and 90° – x are Use MCQ Questions for Class 7 Maths with Answers during preparation and score maximum marks in … Solution: ∠6 = ∠7 [Alternate exterior angles] Then, Find ∠PQR. (a) ∠1 = ∠5 (b) ∠4 = ∠8 (c) ∠5 = ∠8 (d) ∠3 = ∠7 Solution: This chapter deals with the basics of Geometry, parallel lines and transversal, pair of lines, angles and its types, Related angles and interior and exterior angles of triangles. (a) 60°, 30° (b) 70°, 40° Question 2: In parts (a) and (b) given below, it may help to trace the diagrams and draw and measure angles. (b) complementary angles. ∠ABD and ∠DBC; ∠ABE and ∠CBE are linear pairs. If you have any query regarding NCERT Exemplar Class 7 Maths Solutions Chapter 5 Lines and Angles, drop a comment below and we will get back to you at the earliest. We know that, the sum of angles forming linear pair is 180°. In the given figure, POQ is a line. Now, CH || DF and CD is a transversal. Give reason in support of your answer. ⇒ y = 90° – 60° = 30° Find ∠AOD. Solution : \(\Rightarrow x=\frac{300^{\circ}}{3}=100^{\circ}\) (d) Since, sum of the angles about a point is 360° but ∠a ≠ ∠d, Question 12. Solution : Give reason in support of your answer. In the given figure, lines PQ and ST intersect at 0. Question 63: (b) 30° Solution: Solution: In a pair of complementary angles, each angle cannot be more than _________ In the given figure, PQ is a mirror, AB is the incident ray and BC is the reflected ray. 5. Now, SOT is a straight line \(\Rightarrow x=\frac{180^{\circ}}{3}=60^{\circ}\) Solution : Solution: Solution: Solution : Distinct. They are lined up in a straight line in front of the goalpost [See fig.(i)). b: If a transversal intersects, two other lines, then the sum of two interior angles on the same side of the transversal is 180°. Check NCERT Solutions for Class 7 Mathematics. Solution : ∴ Angles between South and West and South and East are making a linear pair. (c) 79° (d) 101° ⇒ 5a = 180° + 20° = 200° (ii) d and e (a) Seven football players are practicing their kicks. (a) complementary sum of interior angles on the same side of a transversal is _________ (a) pair of complementary angles. Here we have provided NCERT Exemplar Problems Solutions along with NCERT Exemplar Problems Class 7.. Solution : ⇒ x + 4x = 720° (c) vertically opposite (d) making a linear pair Question 23: In the given figure, if PQ || RS and QR || TS, then the value of a is Solution: In the given figure, PA || BC || DT and AB || DC. (b) 50° Since, the sum of given two angles is 90°. Class 7 Maths Lines and Angles . Two supplementary angles are always obtuse angles. In the given figure, two parallel lines l and m are cut by two transversals n and p. Find the values of x and y. ⇒ 3x = 180° – x ⇒ 3x + x = 180° ⇒ x = 150°. (a) ∠1 = ∠3 Solution : Question 103: ; Question 92: (c) 45° Solution : Question 33: (a) both (I) and (II) are true (b) (I) is true and (II) is false Sum of angles of linear pair is 180°. Then, its supplement will be (180°-x). ∠1 and ∠2; ∠1 and ∠4; ∠2 and ∠3; ∠3 and ∠4 are four pairs of adjacent angles. ∴ ∠RSC + ∠CSF = 180° [Linear pair] Question 96. ⇒ ∠2 = 180° – 135° = 45° In the given figure, two parallel lines l and m are cut by two transversals n and p. Find the values of x and y. Solution: Free PDF download of Important Questions with solutions for CBSE Class 7 Maths Chapter 5 - Lines and Angles prepared by expert Mathematics teachers from latest edition of CBSE(NCERT) books. NCERT Exemplar Class 7 Maths Book PDF Download Chapter 5 Lines and Angles Solutions Multiple Choice Questions (MCQs) Question 1: The angles between North and West and South and East are (a) complementary (b) supplementary (c) both are acute (d) both are obtuse Solution : From the above figure, it is clear that the […] If one of them is one-third of the other, find the angles. ∴ ∠PQR – ∠QRS = 85° ———– (i) [Alternate interior angles] ⇒ ∠2 = (3 × 36 – b)° = (108 – b)°, Question 36. I: If two lines intersect, then the vertically opposite angles are equal. (b) two pairs of supplementary angles. ∴ ∠SQR, ∠SQP; ∠TQR, ∠TQP are pair so supplementary angles. A linear pair either have both right angles or one acute and one obtuse angle, because angles forming linear pair is 180°. (b) (3 – 6)° A linear pair is a pair of adjacent angles whose non-common sides are opposite rays. Use MCQ Questions for Class 7 Maths with Answers during preparation and score maximum marks in … Question 16: Then, sum of two right angles will be (90°+ 90°) = 180°. As, if we subtract an obtuse angle from 180°, we get an angle which is less than 90°. Solution: (c) one of its angles is right? and x – y = 30° ——— (ii) [Given] Solution: Question 83: As vertically opposite angles are always equal but do not form a linear pair. Question 50: (c) From the above figure, ∠5 and ∠8 are alternate interior angles. (d) From the given figure, we can say that. (d) supplementary All answers have been explained in a step by step manner with detailed solutions to each and every question.In this chapter, we will learn:What are line, ray, line segmentsWhat arecomple ... NCERT Solutions. Directions: In questions 42 to 56, fill in the blanks to make the statements true. Solution : (c) both are acute Since, PQ || RT and RQ is transversal. (a) 95° (b) 100° Solution: Solution: (a) 36° Question 61: Thus, the required angles are 60° and 30°. If the complement of an angle is 62°, then find its supplement. In this section of, NCERT solutions for class 7 Maths chapter 5 lines and angles, we discuss about some basic properties of triangle. ∴ ∠4 = 75° [Alternate interior angles], Question 91. ∠POR + 5 ∠POR = 90° Question 21: One obtuse angle and one acute angle can make a pair of supplementary angles. (a) ∠TOS and ∠SQR is a pair of complementary angles. \(\Rightarrow \quad a=\frac{180}{5}=36\) ∴ ∠ABP + ∠ABC + ∠CBQ = 180° Therefore, B will be less than 45°. (b) Let the angle be x°. If ∠ABC = 46°, then ∠ABP is equal to From the above figure, it is clear that the angle between North and West is 90° and Since, l, m are parallel lines and t is transversal. NCERT Exemplar for Class 7 Maths Chapter 5 Lines and Angles With Solution . (i) Since, PQ || UT and PT is a transversal. (d) 80°,100 Solution : Solution : False Vertically opposite angles are always (d) supplementary angles CBSE Maths notes, CBSE physics notes, CBSE chemistry notes. ⇒ x = 180° – 61° = 119° We hope the NCERT Exemplar Class 7 Maths Chapter 5 Lines and Angles will help you. Solution : Solution : In the given figure, line l intersects two parallel lines PQ and RS. Two angles forming a________pair are supplementary. An angle is 45°. Question 25. 90°, Question 55. Write down each pair of adjacent angles shown in the following figures. Question 112. Question 88: Write the correct one. 60°: Let the angle be x. Directions: In questions 1 to 41, there are four options out of which one is correct. (i) Let the angle between b and c is ∠1. Distinct (iii) d and f (iv) c and f For given figure, statements p and q are given below: It is given that, the angle is four times its supplement. In the given figure, if QP || SR, the value of a is (ii) Supplementary (i) AB || CD (a) 125° Solution : ⇒ a = 180° – 100° = 80°. What is the type of other angle of a linear pair, if Two right angles are complementary to each other. Given that \(\frac{x}{y}=\frac{3}{2}\) 2x + 2x + 2 = 90° Thus, m || n as the sum of co-interior angles is 180°. Question 42: Find the values of a, b and c. (i) b and c (ii) d and e Question 51: ⇒ ∠2 = 180° – 42° – 68° [Using (i)] \(\Rightarrow x=\frac{180^{\circ}}{5}=36^{\circ}\) x = 2(180° – x) – 60° Let one angle be 2x and the other angle be 2x + 2. (a) Since, POR is a straight line. ∴ AOB is a straight line. 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